(5y^2+7y+1)(4y-3)=0

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Solution for (5y^2+7y+1)(4y-3)=0 equation: 


Simplifying
(5y2 + 7y + 1)(4y + -3) = 0

Reorder the terms:
(1 + 7y + 5y2)(4y + -3) = 0

Reorder the terms:
(1 + 7y + 5y2)(-3 + 4y) = 0

Multiply (1 + 7y + 5y2) * (-3 + 4y)
(1(-3 + 4y) + 7y * (-3 + 4y) + 5y2 * (-3 + 4y)) = 0
((-3 * 1 + 4y * 1) + 7y * (-3 + 4y) + 5y2 * (-3 + 4y)) = 0
((-3 + 4y) + 7y * (-3 + 4y) + 5y2 * (-3 + 4y)) = 0
(-3 + 4y + (-3 * 7y + 4y * 7y) + 5y2 * (-3 + 4y)) = 0
(-3 + 4y + (-21y + 28y2) + 5y2 * (-3 + 4y)) = 0
(-3 + 4y + -21y + 28y2 + (-3 * 5y2 + 4y * 5y2)) = 0
(-3 + 4y + -21y + 28y2 + (-15y2 + 20y3)) = 0

Combine like terms: 4y + -21y = -17y
(-3 + -17y + 28y2 + -15y2 + 20y3) = 0

Combine like terms: 28y2 + -15y2 = 13y2
(-3 + -17y + 13y2 + 20y3) = 0

Solving
-3 + -17y + 13y2 + 20y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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